What are the solutions to the equation x^2+22x=0 ?

The solutions to the equation x^2+22x=0 are x=0,x=-22

Find the zeros of x^2+22x=0

The zeros of x^2+22x=0 are x=0,x=-22

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 22 x = 0

x = 0, x = - 22

Solution steps

x^{2} + 22 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 0 = 22

x_{1, 2} = \frac{- 22 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 22}{2 \cdot 1}, x_{2} = \frac{- 22 - 22}{2 \cdot 1}

x = \frac{- 22 + 22}{2 \cdot 1} : 0

x = \frac{- 22 - 22}{2 \cdot 1} : - 22

The solutions to the quadratic equation are:

x = 0, x = - 22

x^{2} + 6 x + 9 = 81

6 x^{2} - 3 x - 3 = 0

3 x^{2} - 2 x - 20 = 0

(x + 8)^{2} = 81

2 x^{2} + x - 105 = 0

What are the solutions to the equation x^2+22x=0 ?
The solutions to the equation x^2+22x=0 are x=0,x=-22
Find the zeros of x^2+22x=0
The zeros of x^2+22x=0 are x=0,x=-22