What are the solutions to the equation 2x^2+x-105=0 ?

The solutions to the equation 2x^2+x-105=0 are x=7,x=-15/2

Find the zeros of 2x^2+x-105=0

The zeros of 2x^2+x-105=0 are x=7,x=-15/2

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2 x^{2} + x - 105 = 0

x = 7, x = - \frac{15}{2}

Decimal Notation

x = 7, x = - 7.5

Solution steps

2 x^{2} + x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 105 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 105) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 2}, x_{2} = \frac{- 1 - 29}{2 \cdot 2}

x = \frac{- 1 + 29}{2 \cdot 2} : 7

x = \frac{- 1 - 29}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = 7, x = - \frac{15}{2}

- x^{2} + 12 = x

3 x^{2} - 2 x - 2 = - 1

x^{2} + (n + 1) x + n = 0

5 x^{2} + 9 x + 1

x^{2} - 8 x + 12 = 0

What are the solutions to the equation 2x^2+x-105=0 ?
The solutions to the equation 2x^2+x-105=0 are x=7,x=-15/2
Find the zeros of 2x^2+x-105=0
The zeros of 2x^2+x-105=0 are x=7,x=-15/2