What are the solutions to the equation x^2+20x+109=0 ?

The solutions to the equation x^2+20x+109=0 are x=-10+3i,x=-10-3i

Find the zeros of x^2+20x+109=0

The zeros of x^2+20x+109=0 are x=-10+3i,x=-10-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 20 x + 109 = 0

x = - 10 + 3 i, x = - 10 - 3 i

Solution steps

x^{2} + 20 x + 109 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 109}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 109 : 6 i

x_{1, 2} = \frac{- 20 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 6 i}{2 \cdot 1}

x = \frac{- 20 + 6 i}{2 \cdot 1} : - 10 + 3 i

x = \frac{- 20 - 6 i}{2 \cdot 1} : - 10 - 3 i

The solutions to the quadratic equation are:

x = - 10 + 3 i, x = - 10 - 3 i

x^{2} - 8 x - 105 = 0

4 x^{2} - 4 x + 1 = 0

x, x^{2} - 8 x y + y^{2} = 8

x^{2} - \frac{1}{2} x

(3 x - 5)^{2} = 49

What are the solutions to the equation x^2+20x+109=0 ?
The solutions to the equation x^2+20x+109=0 are x=-10+3i,x=-10-3i
Find the zeros of x^2+20x+109=0
The zeros of x^2+20x+109=0 are x=-10+3i,x=-10-3i