What are the solutions to the equation 2x^2+14x+3=-17 ?

The solutions to the equation 2x^2+14x+3=-17 are x=-2,x=-5

Find the zeros of 2x^2+14x+3=-17

The zeros of 2x^2+14x+3=-17 are x=-2,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 14 x + 3 = - 17

x = - 2, x = - 5

Solution steps

2 x^{2} + 14 x + 3 = - 17

Move

17

to the left side

2 x^{2} + 14 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

1 4^{2} - 4 \cdot 2 \cdot 20 = 6

x_{1, 2} = \frac{- 14 \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 14 + 6}{2 \cdot 2}, x_{2} = \frac{- 14 - 6}{2 \cdot 2}

x = \frac{- 14 + 6}{2 \cdot 2} : - 2

x = \frac{- 14 - 6}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

2 x^{2} - 14 x + 1 = 0

x^{2} - 4 x = 0

4 x^{2} + 24 x - 4 = 0

2 x^{2} - 40 = - 140

2^{2} + 4^{2} = x^{2}

What are the solutions to the equation 2x^2+14x+3=-17 ?
The solutions to the equation 2x^2+14x+3=-17 are x=-2,x=-5
Find the zeros of 2x^2+14x+3=-17
The zeros of 2x^2+14x+3=-17 are x=-2,x=-5