What are the solutions to the equation 2x^2-14x+1=0 ?

The solutions to the equation 2x^2-14x+1=0 are x=(7+sqrt(47))/2 ,x=(7-sqrt(47))/2

Find the zeros of 2x^2-14x+1=0

The zeros of 2x^2-14x+1=0 are x=(7+sqrt(47))/2 ,x=(7-sqrt(47))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 14 x + 1 = 0

x = \frac{7 + 47}{2}, x = \frac{7 - 47}{2}

Decimal Notation

x = 6.92782 \dots, x = 0.07217 \dots

Solution steps

2 x^{2} - 14 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 \cdot 1 = 247

x_{1, 2} = \frac{- ( - 14 ) \pm 2 47}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 47}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2 47}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2 47}{2 \cdot 2} : \frac{7 + 47}{2}

x = \frac{- ( - 14 ) - 2 47}{2 \cdot 2} : \frac{7 - 47}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 47}{2}, x = \frac{7 - 47}{2}

x^{2} - 4 x = 0

4 x^{2} + 24 x - 4 = 0

2 x^{2} - 40 = - 140

2^{2} + 4^{2} = x^{2}

8 x^{2} = 72

What are the solutions to the equation 2x^2-14x+1=0 ?
The solutions to the equation 2x^2-14x+1=0 are x=(7+sqrt(47))/2 ,x=(7-sqrt(47))/2
Find the zeros of 2x^2-14x+1=0
The zeros of 2x^2-14x+1=0 are x=(7+sqrt(47))/2 ,x=(7-sqrt(47))/2