What are the solutions to the equation x^2+2x=-20 ?

The solutions to the equation x^2+2x=-20 are x=-1+sqrt(19)i,x=-1-sqrt(19)i

Find the zeros of x^2+2x=-20

The zeros of x^2+2x=-20 are x=-1+sqrt(19)i,x=-1-sqrt(19)i

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x^{2} + 2 x = - 20

x = - 1 + 19 i, x = - 1 - 19 i

Solution steps

x^{2} + 2 x = - 20

Move

20

to the left side

x^{2} + 2 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 20 : 219 i

x_{1, 2} = \frac{- 2 \pm 2 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 19 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 19 i}{2 \cdot 1}

x = \frac{- 2 + 2 19 i}{2 \cdot 1} : - 1 + 19 i

x = \frac{- 2 - 2 19 i}{2 \cdot 1} : - 1 - 19 i

The solutions to the quadratic equation are:

x = - 1 + 19 i, x = - 1 - 19 i

14 x^{2} - 21 x = 0

- 8 x^{2} + 5 = - 4 x

(x - 8)^{2} + (x - 1)^{2} = x^{2}

4 x^{2} - 20 x + 21 = 0

x^{2} - 8 x + 17

What are the solutions to the equation x^2+2x=-20 ?
The solutions to the equation x^2+2x=-20 are x=-1+sqrt(19)i,x=-1-sqrt(19)i
Find the zeros of x^2+2x=-20
The zeros of x^2+2x=-20 are x=-1+sqrt(19)i,x=-1-sqrt(19)i