What are the solutions to the equation -8x^2+5=-4x ?

The solutions to the equation -8x^2+5=-4x are x=-(-1+sqrt(11))/4 ,x=(1+sqrt(11))/4

Find the zeros of -8x^2+5=-4x

The zeros of -8x^2+5=-4x are x=-(-1+sqrt(11))/4 ,x=(1+sqrt(11))/4

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- 8 x^{2} + 5 = - 4 x

x = - \frac{- 1 + 11}{4}, x = \frac{1 + 11}{4}

Decimal Notation

x = - 0.57915 \dots, x = 1.07915 \dots

Solution steps

- 8 x^{2} + 5 = - 4 x

Move

4 x

to the left side

- 8 x^{2} + 5 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 8 x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 8 ) \cdot 5}{2 ( - 8 )}

4^{2} - 4 (- 8) \cdot 5 = 411

x_{1, 2} = \frac{- 4 \pm 4 11}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 11}{2 ( - 8 )}, x_{2} = \frac{- 4 - 4 11}{2 ( - 8 )}

x = \frac{- 4 + 4 11}{2 ( - 8 )} : - \frac{- 1 + 11}{4}

x = \frac{- 4 - 4 11}{2 ( - 8 )} : \frac{1 + 11}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 11}{4}, x = \frac{1 + 11}{4}

(x - 8)^{2} + (x - 1)^{2} = x^{2}

4 x^{2} - 20 x + 21 = 0

x^{2} - 8 x + 17

d = \frac{1}{2} a t^{2}

- 4 x^{2} - 20 x - 25 = 0

What are the solutions to the equation -8x^2+5=-4x ?
The solutions to the equation -8x^2+5=-4x are x=-(-1+sqrt(11))/4 ,x=(1+sqrt(11))/4
Find the zeros of -8x^2+5=-4x
The zeros of -8x^2+5=-4x are x=-(-1+sqrt(11))/4 ,x=(1+sqrt(11))/4