What are the solutions to the equation 4x^2-20x+21=0 ?

The solutions to the equation 4x^2-20x+21=0 are x= 7/2 ,x= 3/2

Find the zeros of 4x^2-20x+21=0

The zeros of 4x^2-20x+21=0 are x= 7/2 ,x= 3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 20 x + 21 = 0

x = \frac{7}{2}, x = \frac{3}{2}

Decimal Notation

x = 3.5, x = 1.5

Solution steps

4 x^{2} - 20 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 21 = 8

x_{1, 2} = \frac{- ( - 20 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 8}{2 \cdot 4}

x = \frac{- ( - 20 ) + 8}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 20 ) - 8}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{3}{2}

x^{2} - 8 x + 17

d = \frac{1}{2} a t^{2}

- 4 x^{2} - 20 x - 25 = 0

3 x^{2} - 2 x - 2 = 4

(6 x - 5) (2 x - 9) = 0

What are the solutions to the equation 4x^2-20x+21=0 ?
The solutions to the equation 4x^2-20x+21=0 are x= 7/2 ,x= 3/2
Find the zeros of 4x^2-20x+21=0
The zeros of 4x^2-20x+21=0 are x= 7/2 ,x= 3/2