What are the solutions to the equation -4x^2-20x-25=0 ?

The solutions to the equation -4x^2-20x-25=0 are x=-5/2

Find the zeros of -4x^2-20x-25=0

The zeros of -4x^2-20x-25=0 are x=-5/2

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- 4 x^{2} - 20 x - 25 = 0

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

- 4 x^{2} - 20 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 4 ) ( - 25 )}{2 ( - 4 )}

(- 20)^{2} - 4 (- 4) (- 25) = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 ( - 4 )}

x = \frac{- ( - 20 )}{2 ( - 4 )}

\frac{- ( - 20 )}{2 ( - 4 )} = - \frac{5}{2}

x = - \frac{5}{2}

The solution to the quadratic equation is:

x = - \frac{5}{2}

3 x^{2} - 2 x - 2 = 4

(6 x - 5) (2 x - 9) = 0

4 a^{2} + 6 a - 6 = - 3

(x - 2) (x + 2) = 11 x - 4

12 x^{2} - 180 x + 500 = 0

What are the solutions to the equation -4x^2-20x-25=0 ?
The solutions to the equation -4x^2-20x-25=0 are x=-5/2
Find the zeros of -4x^2-20x-25=0
The zeros of -4x^2-20x-25=0 are x=-5/2