What are the solutions to the equation (6x-5)(2x-9)=0 ?

The solutions to the equation (6x-5)(2x-9)=0 are x= 5/6 ,x= 9/2

Find the zeros of (6x-5)(2x-9)=0

The zeros of (6x-5)(2x-9)=0 are x= 5/6 ,x= 9/2

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(6 x - 5) (2 x - 9) = 0

x = \frac{5}{6}, x = \frac{9}{2}

Decimal Notation

x = 0.83333 \dots, x = 4.5

Solution steps

(6 x - 5) (2 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

6 x - 5 = 0 or 2 x - 9 = 0

Solve

6 x - 5 = 0 : x = \frac{5}{6}

Solve

2 x - 9 = 0 : x = \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = \frac{9}{2}

4 a^{2} + 6 a - 6 = - 3

(x - 2) (x + 2) = 11 x - 4

12 x^{2} - 180 x + 500 = 0

3 p^{2} + 4 p = 8

34 = 105 t - 16 t^{2}

What are the solutions to the equation (6x-5)(2x-9)=0 ?
The solutions to the equation (6x-5)(2x-9)=0 are x= 5/6 ,x= 9/2
Find the zeros of (6x-5)(2x-9)=0
The zeros of (6x-5)(2x-9)=0 are x= 5/6 ,x= 9/2