What are the solutions to the equation z(z+7)=30 ?

The solutions to the equation z(z+7)=30 are z=3,z=-10

Find the zeros of z(z+7)=30

The zeros of z(z+7)=30 are z=3,z=-10

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z (z + 7) = 30

z = 3, z = - 10

Solution steps

z (z + 7) = 30

Expand

z (z + 7) : z^{2} + 7 z

z^{2} + 7 z = 30

Move

30

to the left side

z^{2} + 7 z - 30 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 30) = 13

z_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 7 + 13}{2 \cdot 1}, z_{2} = \frac{- 7 - 13}{2 \cdot 1}

z = \frac{- 7 + 13}{2 \cdot 1} : 3

z = \frac{- 7 - 13}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

z = 3, z = - 10

m^{2} - 8 m + 15 = 0

4 + 8 + 12 + 4 n = 2 n (n + 1)

12 x^{2} + 9 x - 2 = - 17

3 y^{2} - 1 = 0

x^{2} + 24 x = 52

What are the solutions to the equation z(z+7)=30 ?
The solutions to the equation z(z+7)=30 are z=3,z=-10
Find the zeros of z(z+7)=30
The zeros of z(z+7)=30 are z=3,z=-10