What are the solutions to the equation 4(6-5x)^2+11=20 ?

The solutions to the equation 4(6-5x)^2+11=20 are x= 9/10 ,x= 3/2

Find the zeros of 4(6-5x)^2+11=20

The zeros of 4(6-5x)^2+11=20 are x= 9/10 ,x= 3/2

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4 (6 - 5 x)^{2} + 11 = 20

x = \frac{9}{10}, x = \frac{3}{2}

Decimal Notation

x = 0.9, x = 1.5

Solution steps

4 (6 - 5 x)^{2} + 11 = 20

Move

11

to the right side

4 (6 - 5 x)^{2} = 9

Divide both sides by

4

(6 - 5 x)^{2} = \frac{9}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 - 5 x = \frac{9}{4} : x = \frac{9}{10}

Solve

6 - 5 x = - \frac{9}{4} : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{9}{10}, x = \frac{3}{2}

3 x^{2} + 12 x - 3 = 0

5 x^{2} + 3 x = 6 - 4 x

3 x^{2} - 5 x - 28 = 0

8 x^{2} - 6 x = 9

6 x^{2} + 10 x - 3 = 0

What are the solutions to the equation 4(6-5x)^2+11=20 ?
The solutions to the equation 4(6-5x)^2+11=20 are x= 9/10 ,x= 3/2
Find the zeros of 4(6-5x)^2+11=20
The zeros of 4(6-5x)^2+11=20 are x= 9/10 ,x= 3/2