What are the solutions to the equation 5x^2+3x=6-4x ?

The solutions to the equation 5x^2+3x=6-4x are x= 3/5 ,x=-2

Find the zeros of 5x^2+3x=6-4x

The zeros of 5x^2+3x=6-4x are x= 3/5 ,x=-2

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5 x^{2} + 3 x = 6 - 4 x

x = \frac{3}{5}, x = - 2

Decimal Notation

x = 0.6, x = - 2

Solution steps

5 x^{2} + 3 x = 6 - 4 x

Move

4 x

to the left side

5 x^{2} + 7 x = 6

Move

6

to the left side

5 x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 6) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 5}, x_{2} = \frac{- 7 - 13}{2 \cdot 5}

x = \frac{- 7 + 13}{2 \cdot 5} : \frac{3}{5}

x = \frac{- 7 - 13}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 2

3 x^{2} - 5 x - 28 = 0

8 x^{2} - 6 x = 9

6 x^{2} + 10 x - 3 = 0

3 m^{2} - 7 m = 5

m^{2} - 4 m - 2 = 0

What are the solutions to the equation 5x^2+3x=6-4x ?
The solutions to the equation 5x^2+3x=6-4x are x= 3/5 ,x=-2
Find the zeros of 5x^2+3x=6-4x
The zeros of 5x^2+3x=6-4x are x= 3/5 ,x=-2