What are the solutions to the equation 6x^2+10x-3=0 ?

The solutions to the equation 6x^2+10x-3=0 are x=(-5+sqrt(43))/6 ,x=-(5+sqrt(43))/6

Find the zeros of 6x^2+10x-3=0

The zeros of 6x^2+10x-3=0 are x=(-5+sqrt(43))/6 ,x=-(5+sqrt(43))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 10 x - 3 = 0

x = \frac{- 5 + 43}{6}, x = - \frac{5 + 43}{6}

Decimal Notation

x = 0.25957 \dots, x = - 1.92623 \dots

Solution steps

6 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

1 0^{2} - 4 \cdot 6 (- 3) = 243

x_{1, 2} = \frac{- 10 \pm 2 43}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 10 + 2 43}{2 \cdot 6}, x_{2} = \frac{- 10 - 2 43}{2 \cdot 6}

x = \frac{- 10 + 2 43}{2 \cdot 6} : \frac{- 5 + 43}{6}

x = \frac{- 10 - 2 43}{2 \cdot 6} : - \frac{5 + 43}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 43}{6}, x = - \frac{5 + 43}{6}

3 m^{2} - 7 m = 5

m^{2} - 4 m - 2 = 0

6 x^{2} - 10 x + 3 = 0

x, 4 x^{2} - 4 x y + 1 - y^{2} = 0

x^{2} - 5 x - 25 = 0

What are the solutions to the equation 6x^2+10x-3=0 ?
The solutions to the equation 6x^2+10x-3=0 are x=(-5+sqrt(43))/6 ,x=-(5+sqrt(43))/6
Find the zeros of 6x^2+10x-3=0
The zeros of 6x^2+10x-3=0 are x=(-5+sqrt(43))/6 ,x=-(5+sqrt(43))/6