What are the solutions to the equation m^2-4m-2=0 ?

The solutions to the equation m^2-4m-2=0 are m=2+sqrt(6),m=2-sqrt(6)

Find the zeros of m^2-4m-2=0

The zeros of m^2-4m-2=0 are m=2+sqrt(6),m=2-sqrt(6)

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m^{2} - 4 m - 2 = 0

m = 2 + 6, m = 2 - 6

Decimal Notation

m = 4.44948 \dots, m = - 0.44948 \dots

Solution steps

m^{2} - 4 m - 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 2) = 26

m_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 1}

m = \frac{- ( - 4 ) + 2 6}{2 \cdot 1} : 2 + 6

m = \frac{- ( - 4 ) - 2 6}{2 \cdot 1} : 2 - 6

The solutions to the quadratic equation are:

m = 2 + 6, m = 2 - 6

6 x^{2} - 10 x + 3 = 0

x, 4 x^{2} - 4 x y + 1 - y^{2} = 0

x^{2} - 5 x - 25 = 0

x^{2} - 4 x - 21 = 0

x^{2} + 2 x + 1

What are the solutions to the equation m^2-4m-2=0 ?
The solutions to the equation m^2-4m-2=0 are m=2+sqrt(6),m=2-sqrt(6)
Find the zeros of m^2-4m-2=0
The zeros of m^2-4m-2=0 are m=2+sqrt(6),m=2-sqrt(6)