What are the solutions to the equation 5x^2-17x-12=0 ?

The solutions to the equation 5x^2-17x-12=0 are x=4,x=-3/5

Find the zeros of 5x^2-17x-12=0

The zeros of 5x^2-17x-12=0 are x=4,x=-3/5

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5 x^{2} - 17 x - 12 = 0

x = 4, x = - \frac{3}{5}

Decimal Notation

x = 4, x = - 0.6

Solution steps

5 x^{2} - 17 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 (- 12) = 23

x_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 5}, x_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 5}

x = \frac{- ( - 17 ) + 23}{2 \cdot 5} : 4

x = \frac{- ( - 17 ) - 23}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = 4, x = - \frac{3}{5}

x^{2} + 49 = 14 x

2 x^{2} - 25 = 0

x^{2} = 1 5^{2} + 8^{2}

x^{2} + 3 x - 8

X^{2} - 3 X + 2 = 0

What are the solutions to the equation 5x^2-17x-12=0 ?
The solutions to the equation 5x^2-17x-12=0 are x=4,x=-3/5
Find the zeros of 5x^2-17x-12=0
The zeros of 5x^2-17x-12=0 are x=4,x=-3/5