What are the solutions to the equation completesquare 10x^2-19x+6 ?

The solutions to the equation completesquare 10x^2-19x+6 are 10(x-19/20)^2-121/40

Find the zeros of completesquare 10x^2-19x+6

The zeros of completesquare 10x^2-19x+6 are 10(x-19/20)^2-121/40

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complete the square

10 x^{2} - 19 x + 6

10 (x - \frac{19}{20})^{2} - \frac{121}{40}

Solution steps

10 x^{2} - 19 x + 6

Write

10 x^{2} - 19 x + 6

in the form:

x^{2} + 2 a x + a^{2}

Factor out

10

10 (x^{2} - \frac{19 x}{10} + \frac{3}{5})

2 a = - \frac{19}{10} : a = - \frac{19}{20}

Add and subtract

(- \frac{19}{20})^{2}

10 (x^{2} - \frac{19 x}{10} + \frac{3}{5} + (- \frac{19}{20})^{2} - (- \frac{19}{20})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - \frac{19}{10} x + (- \frac{19}{20})^{2} = (x - \frac{19}{20})^{2}

10 ((x - \frac{19}{20})^{2} + \frac{3}{5} - (- \frac{19}{20})^{2})

Simplify

10 (x - \frac{19}{20})^{2} - \frac{121}{40}

2 x^{2} + 12 x + 6 = 0

x^{2} + 17 x + 70 = 0

x (x - 3) = 5 x + 1

x^{2} - 4 x + 1 = 0

0 = - 4.9 t^{2} + 19.6 t + 58.8

What are the solutions to the equation completesquare 10x^2-19x+6 ?
The solutions to the equation completesquare 10x^2-19x+6 are 10(x-19/20)^2-121/40
Find the zeros of completesquare 10x^2-19x+6
The zeros of completesquare 10x^2-19x+6 are 10(x-19/20)^2-121/40