What are the solutions to the equation 2x^2+12x+9=0 ?

The solutions to the equation 2x^2+12x+9=0 are x=(3(sqrt(2)-2))/2 ,x=-(3(2+sqrt(2)))/2

Find the zeros of 2x^2+12x+9=0

The zeros of 2x^2+12x+9=0 are x=(3(sqrt(2)-2))/2 ,x=-(3(2+sqrt(2)))/2

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2 x^{2} + 12 x + 9 = 0

x = \frac{3 ( 2 - 2 )}{2}, x = - \frac{3 ( 2 + 2 )}{2}

Decimal Notation

x = - 0.87867 \dots, x = - 5.12132 \dots

Solution steps

2 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 9 = 62

x_{1, 2} = \frac{- 12 \pm 6 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 6 2}{2 \cdot 2}, x_{2} = \frac{- 12 - 6 2}{2 \cdot 2}

x = \frac{- 12 + 6 2}{2 \cdot 2} : \frac{3 ( 2 - 2 )}{2}

x = \frac{- 12 - 6 2}{2 \cdot 2} : - \frac{3 ( 2 + 2 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 - 2 )}{2}, x = - \frac{3 ( 2 + 2 )}{2}

10 x^{2} - 19 x + 6

2 x^{2} + 12 x + 6 = 0

x^{2} + 17 x + 70 = 0

x (x - 3) = 5 x + 1

x^{2} - 4 x + 1 = 0

What are the solutions to the equation 2x^2+12x+9=0 ?
The solutions to the equation 2x^2+12x+9=0 are x=(3(sqrt(2)-2))/2 ,x=-(3(2+sqrt(2)))/2
Find the zeros of 2x^2+12x+9=0
The zeros of 2x^2+12x+9=0 are x=(3(sqrt(2)-2))/2 ,x=-(3(2+sqrt(2)))/2