What are the solutions to the equation 2x^2+12x+6=0 ?

The solutions to the equation 2x^2+12x+6=0 are x=-3+sqrt(6),x=-3-sqrt(6)

Find the zeros of 2x^2+12x+6=0

The zeros of 2x^2+12x+6=0 are x=-3+sqrt(6),x=-3-sqrt(6)

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2 x^{2} + 12 x + 6 = 0

x = - 3 + 6, x = - 3 - 6

Decimal Notation

x = - 0.55051 \dots, x = - 5.44948 \dots

Solution steps

2 x^{2} + 12 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 \cdot 6 = 46

x_{1, 2} = \frac{- 12 \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 6}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 6}{2 \cdot 2}

x = \frac{- 12 + 4 6}{2 \cdot 2} : - 3 + 6

x = \frac{- 12 - 4 6}{2 \cdot 2} : - 3 - 6

The solutions to the quadratic equation are:

x = - 3 + 6, x = - 3 - 6

x^{2} + 17 x + 70 = 0

x (x - 3) = 5 x + 1

x^{2} - 4 x + 1 = 0

0 = - 4.9 t^{2} + 19.6 t + 58.8

x, x^{2} - 6 x + 10 = 0

What are the solutions to the equation 2x^2+12x+6=0 ?
The solutions to the equation 2x^2+12x+6=0 are x=-3+sqrt(6),x=-3-sqrt(6)
Find the zeros of 2x^2+12x+6=0
The zeros of 2x^2+12x+6=0 are x=-3+sqrt(6),x=-3-sqrt(6)