What are the solutions to the equation completesquare x^2-4x+1=0 ?

The solutions to the equation completesquare x^2-4x+1=0 are x=sqrt(3)+2,x=-sqrt(3)+2

Find the zeros of completesquare x^2-4x+1=0

The zeros of completesquare x^2-4x+1=0 are x=sqrt(3)+2,x=-sqrt(3)+2

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x^{2} - 4 x + 1 = 0

x = 3 + 2, x = - 3 + 2

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

x^{2} - 4 x + 1 = 0

Move

1

to the right side

x^{2} - 4 x = - 1

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = 3

For

the solutions are

f (x) = a, - a

Solve

x - 2 = 3 : x = 3 + 2

Solve

x - 2 = - 3 : x = - 3 + 2

The solutions to the quadratic equation are:

x = 3 + 2, x = - 3 + 2

0 = - 4.9 t^{2} + 19.6 t + 58.8

x, x^{2} - 6 x + 10 = 0

289 = x^{2}

x^{2} + 3 x - 19 = 0

(5 - 22) x^{2} - (4 + 22) x - 2 = 0

What are the solutions to the equation completesquare x^2-4x+1=0 ?
The solutions to the equation completesquare x^2-4x+1=0 are x=sqrt(3)+2,x=-sqrt(3)+2
Find the zeros of completesquare x^2-4x+1=0
The zeros of completesquare x^2-4x+1=0 are x=sqrt(3)+2,x=-sqrt(3)+2