What are the solutions to the equation 0=-4.9t^2+19.6t+58.8 ?

The solutions to the equation 0=-4.9t^2+19.6t+58.8 are t=-2,t=6

Find the zeros of 0=-4.9t^2+19.6t+58.8

The zeros of 0=-4.9t^2+19.6t+58.8 are t=-2,t=6

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0 = - 4.9 t^{2} + 19.6 t + 58.8

t = - 2, t = 6

Solution steps

0 = - 4.9 t^{2} + 19.6 t + 58.8

Multiply both sides by

10

0 = - 49 t^{2} + 196 t + 588

Switch sides

- 49 t^{2} + 196 t + 588 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 196 \pm 19 6 ^{2} - 4 ( - 49 ) \cdot 588}{2 ( - 49 )}

19 6^{2} - 4 (- 49) \cdot 588 = 392

t_{1, 2} = \frac{- 196 \pm 392}{2 ( - 49 )}

Separate the solutions

t_{1} = \frac{- 196 + 392}{2 ( - 49 )}, t_{2} = \frac{- 196 - 392}{2 ( - 49 )}

t = \frac{- 196 + 392}{2 ( - 49 )} : - 2

t = \frac{- 196 - 392}{2 ( - 49 )} : 6

The solutions to the quadratic equation are:

t = - 2, t = 6

x, x^{2} - 6 x + 10 = 0

289 = x^{2}

x^{2} + 3 x - 19 = 0

(5 - 22) x^{2} - (4 + 22) x - 2 = 0

9 x^{2} + 12 x + 5 = 0

What are the solutions to the equation 0=-4.9t^2+19.6t+58.8 ?
The solutions to the equation 0=-4.9t^2+19.6t+58.8 are t=-2,t=6
Find the zeros of 0=-4.9t^2+19.6t+58.8
The zeros of 0=-4.9t^2+19.6t+58.8 are t=-2,t=6