What are the solutions to the equation 2x^2-6=-4x ?

The solutions to the equation 2x^2-6=-4x are x=1,x=-3

Find the zeros of 2x^2-6=-4x

The zeros of 2x^2-6=-4x are x=1,x=-3

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2 x^{2} - 6 = - 4 x

x = 1, x = - 3

Solution steps

2 x^{2} - 6 = - 4 x

Move

4 x

to the left side

2 x^{2} - 6 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 6) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 2}, x_{2} = \frac{- 4 - 8}{2 \cdot 2}

x = \frac{- 4 + 8}{2 \cdot 2} : 1

x = \frac{- 4 - 8}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

3 x^{2} - 6 x

- 3 x^{2} + 6 = - 1

4 x^{2} - 10 x - 3

3 (x - 2)^{2} = 7

y^{2} - 9 y + 8 = 0

What are the solutions to the equation 2x^2-6=-4x ?
The solutions to the equation 2x^2-6=-4x are x=1,x=-3
Find the zeros of 2x^2-6=-4x
The zeros of 2x^2-6=-4x are x=1,x=-3