What are the solutions to the equation y(y+6)=2 ?

The solutions to the equation y(y+6)=2 are y=-3+sqrt(11),y=-3-sqrt(11)

Find the zeros of y(y+6)=2

The zeros of y(y+6)=2 are y=-3+sqrt(11),y=-3-sqrt(11)

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y (y + 6) = 2

y = - 3 + 11, y = - 3 - 11

Decimal Notation

y = 0.31662 \dots, y = - 6.31662 \dots

Solution steps

y (y + 6) = 2

Expand

y (y + 6) : y^{2} + 6 y

y^{2} + 6 y = 2

Move

2

to the left side

y^{2} + 6 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 2) = 211

y_{1, 2} = \frac{- 6 \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 2 11}{2 \cdot 1}, y_{2} = \frac{- 6 - 2 11}{2 \cdot 1}

y = \frac{- 6 + 2 11}{2 \cdot 1} : - 3 + 11

y = \frac{- 6 - 2 11}{2 \cdot 1} : - 3 - 11

The solutions to the quadratic equation are:

y = - 3 + 11, y = - 3 - 11

x^{2} + 1 = - 8

2 x^{2} + 4 x - 10 = 0

\frac{( x + 2 ) ^{2}}{5} + \frac{( x - 2 ) ^{2}}{3} = \frac{16}{3}

x^{2} - x - 1

(x - 5)^{2} = - 25

What are the solutions to the equation y(y+6)=2 ?
The solutions to the equation y(y+6)=2 are y=-3+sqrt(11),y=-3-sqrt(11)
Find the zeros of y(y+6)=2
The zeros of y(y+6)=2 are y=-3+sqrt(11),y=-3-sqrt(11)