What are the solutions to the equation -4x^2+8=24 ?

The solutions to the equation -4x^2+8=24 are x=2i,x=-2i

Find the zeros of -4x^2+8=24

The zeros of -4x^2+8=24 are x=2i,x=-2i

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- 4 x^{2} + 8 = 24

x = 2 i, x = - 2 i

Solution steps

- 4 x^{2} + 8 = 24

Move

8

to the right side

- 4 x^{2} = 16

Divide both sides by

- 4

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

11 r^{2} + 7 r = 3

(2 a + x)^{2} = 4 a^{2} + 8 a b^{2} + 4 b^{4}

2 x^{2} + 3 x = - 13

3 y^{2} - 8 y + 4 = 0

7 x + 4 x^{2} + 4 = 2

What are the solutions to the equation -4x^2+8=24 ?
The solutions to the equation -4x^2+8=24 are x=2i,x=-2i
Find the zeros of -4x^2+8=24
The zeros of -4x^2+8=24 are x=2i,x=-2i