What are the solutions to the equation q^2+20q=-104 ?

The solutions to the equation q^2+20q=-104 are q=-10+2i,q=-10-2i

Find the zeros of q^2+20q=-104

The zeros of q^2+20q=-104 are q=-10+2i,q=-10-2i

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q^{2} + 20 q = - 104

q = - 10 + 2 i, q = - 10 - 2 i

Solution steps

q^{2} + 20 q = - 104

Move

104

to the left side

q^{2} + 20 q + 104 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 104}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 104 : 4 i

q_{1, 2} = \frac{- 20 \pm 4 i}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 20 + 4 i}{2 \cdot 1}, q_{2} = \frac{- 20 - 4 i}{2 \cdot 1}

q = \frac{- 20 + 4 i}{2 \cdot 1} : - 10 + 2 i

q = \frac{- 20 - 4 i}{2 \cdot 1} : - 10 - 2 i

The solutions to the quadratic equation are:

q = - 10 + 2 i, q = - 10 - 2 i

x^{2} - 27 x + 65 = - 13 x

x^{2} + 14 x + 30 = 0

9 x^{2} + 7 x - 4 = 0

x^{2} - 4 x - 1

x^{2} - 4 x - 5

What are the solutions to the equation q^2+20q=-104 ?
The solutions to the equation q^2+20q=-104 are q=-10+2i,q=-10-2i
Find the zeros of q^2+20q=-104
The zeros of q^2+20q=-104 are q=-10+2i,q=-10-2i