What are the solutions to the equation ax^2+b=0 ?

The solutions to the equation ax^2+b=0 are x=isqrt(b/a),x=-isqrt(b/a);\quad a\ne 0

Find the zeros of ax^2+b=0

The zeros of ax^2+b=0 are x=isqrt(b/a),x=-isqrt(b/a);\quad a\ne 0

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a x^{2} + b = 0

x = i \frac{b}{a}, x = - i \frac{b}{a}; a \neq = 0

Solution steps

a x^{2} + b = 0

Move

b

to the right side

a x^{2} = - b

Divide both sides by

a; a \neq = 0

x^{2} = - \frac{b}{a}; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{b}{a}, x = - - \frac{b}{a}; a \neq = 0

Simplify

- \frac{b}{a} : i \frac{b}{a}

Simplify

- - \frac{b}{a} : - i \frac{b}{a}

x = i \frac{b}{a}, x = - i \frac{b}{a}; a \neq = 0

5 x^{2} = - 30 x

3^{2} + b^{2} = 6^{2}

1 0^{2} + x^{2} = 2 0^{2}

(x + 1)^{2} + (x - 8)^{2} = 45

x^{2} + 6 x + 5 = 0

What are the solutions to the equation ax^2+b=0 ?
The solutions to the equation ax^2+b=0 are x=isqrt(b/a),x=-isqrt(b/a);\quad a\ne 0
Find the zeros of ax^2+b=0
The zeros of ax^2+b=0 are x=isqrt(b/a),x=-isqrt(b/a);\quad a\ne 0