What are the solutions to the equation b^2-8b+16=0 ?

The solutions to the equation b^2-8b+16=0 are b=4

Find the zeros of b^2-8b+16=0

The zeros of b^2-8b+16=0 are b=4

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b^{2} - 8 b + 16 = 0

b = 4

Solution steps

b^{2} - 8 b + 16 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

b_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

b = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

b = 4

The solution to the quadratic equation is:

b = 4

x^{2} + 4 = 1

x, x^{2} - 3 x + 1 = 0

x^{2} - 0.01 = 0.03

104 - 84 x + 12 x^{2} = 0

2 x^{2} - 8 x + 5

What are the solutions to the equation b^2-8b+16=0 ?
The solutions to the equation b^2-8b+16=0 are b=4
Find the zeros of b^2-8b+16=0
The zeros of b^2-8b+16=0 are b=4