What are the solutions to the equation n^2+2n-11=0 ?

The solutions to the equation n^2+2n-11=0 are n=-1+2sqrt(3),n=-1-2sqrt(3)

Find the zeros of n^2+2n-11=0

The zeros of n^2+2n-11=0 are n=-1+2sqrt(3),n=-1-2sqrt(3)

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n^{2} + 2 n - 11 = 0

n = - 1 + 23, n = - 1 - 23

Decimal Notation

n = 2.46410 \dots, n = - 4.46410 \dots

Solution steps

n^{2} + 2 n - 11 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 11) = 43

n_{1, 2} = \frac{- 2 \pm 4 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 2 + 4 3}{2 \cdot 1}, n_{2} = \frac{- 2 - 4 3}{2 \cdot 1}

n = \frac{- 2 + 4 3}{2 \cdot 1} : - 1 + 23

n = \frac{- 2 - 4 3}{2 \cdot 1} : - 1 - 23

The solutions to the quadratic equation are:

n = - 1 + 23, n = - 1 - 23

6 x^{2} - 36 x + 30 = 0

12 x^{2} - 108 = 0

x^{2} - 11 x - 2

x^{2} + 14 x + 39 = 0

x, 9 y^{2} - 18 y - 16 x^{2} + 32 x - 7 = 0

What are the solutions to the equation n^2+2n-11=0 ?
The solutions to the equation n^2+2n-11=0 are n=-1+2sqrt(3),n=-1-2sqrt(3)
Find the zeros of n^2+2n-11=0
The zeros of n^2+2n-11=0 are n=-1+2sqrt(3),n=-1-2sqrt(3)