What are the solutions to the equation solvefor a,a^2+b^2=2ab ?

The solutions to the equation solvefor a,a^2+b^2=2ab are a=b

Find the zeros of solvefor a,a^2+b^2=2ab

The zeros of solvefor a,a^2+b^2=2ab are a=b

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solve for

a, a^{2} + b^{2} = 2 ab

a = b

Solution steps

a^{2} + b^{2} = 2 ab

Move

2 ab

to the left side

a^{2} + b^{2} - 2 ab = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 2 ba + b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 b ) \pm ( - 2 b ) ^{2} - 4 \cdot 1 \cdot b ^{2}}{2 \cdot 1}

(- 2 b)^{2} - 4 \cdot 1 \cdot b^{2} = 0

a_{1, 2} = \frac{- ( - 2 b ) \pm 0}{2 \cdot 1}

a = \frac{- ( - 2 b )}{2 \cdot 1}

Simplify

\frac{- ( - 2 b )}{2 \cdot 1} : b

a = b

The solution to the quadratic equation is:

a = b

4 x^{2} + 6 = - 9 x

3 x (x + 1) + 56 = 5 x + 86 - 2 x

3 x^{2} = 81 - x^{2}

x^{2} - 7 x + 12 = 0

5^{2} + 8^{2} = x^{2}

What are the solutions to the equation solvefor a,a^2+b^2=2ab ?
The solutions to the equation solvefor a,a^2+b^2=2ab are a=b
Find the zeros of solvefor a,a^2+b^2=2ab
The zeros of solvefor a,a^2+b^2=2ab are a=b