What are the solutions to the equation (4x-5)^2=64 ?

The solutions to the equation (4x-5)^2=64 are x= 13/4 ,x=-3/4

Find the zeros of (4x-5)^2=64

The zeros of (4x-5)^2=64 are x= 13/4 ,x=-3/4

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(4 x - 5)^{2} = 64

x = \frac{13}{4}, x = - \frac{3}{4}

Decimal Notation

x = 3.25, x = - 0.75

Solution steps

(4 x - 5)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 5 = 64 : x = \frac{13}{4}

Solve

4 x - 5 = - 64 : x = - \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{13}{4}, x = - \frac{3}{4}

(x + 5) (2 x - 3) = 2 x - 3

x, 4 y^{2} + 9 x^{2} - 24 y - 72 + 144 = 0

- x^{2} + 4.6 x - 5.29 = 0

X^{2} - 6 X + 1 = 0

x, 6 x^{2} y + 5 y^{3} + 3 x^{2} = 12 - x^{2} y^{2}

What are the solutions to the equation (4x-5)^2=64 ?
The solutions to the equation (4x-5)^2=64 are x= 13/4 ,x=-3/4
Find the zeros of (4x-5)^2=64
The zeros of (4x-5)^2=64 are x= 13/4 ,x=-3/4