What are the solutions to the equation (3x-5)^2-1=15 ?

The solutions to the equation (3x-5)^2-1=15 are x=3,x= 1/3

Find the zeros of (3x-5)^2-1=15

The zeros of (3x-5)^2-1=15 are x=3,x= 1/3

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(3 x - 5)^{2} - 1 = 15

x = 3, x = \frac{1}{3}

Decimal Notation

x = 3, x = 0.33333 \dots

Solution steps

(3 x - 5)^{2} - 1 = 15

Move

1

to the right side

(3 x - 5)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 5 = 16 : x = 3

Solve

3 x - 5 = - 16 : x = \frac{1}{3}

The solutions to the quadratic equation are:

x = 3, x = \frac{1}{3}

r, M = π r^{2} h d

- 2 (x + 1)^{2} = 72

3 x^{2} - 6 x = - 2

3 r^{2} + 8 r - 3 = 0

x^{2} + 2 x - 5 = 0

What are the solutions to the equation (3x-5)^2-1=15 ?
The solutions to the equation (3x-5)^2-1=15 are x=3,x= 1/3
Find the zeros of (3x-5)^2-1=15
The zeros of (3x-5)^2-1=15 are x=3,x= 1/3