What are the solutions to the equation -3(2x-5)^2+13=4 ?

The solutions to the equation -3(2x-5)^2+13=4 are x=(sqrt(3)+5)/2 ,x=(-sqrt(3)+5)/2

Find the zeros of -3(2x-5)^2+13=4

The zeros of -3(2x-5)^2+13=4 are x=(sqrt(3)+5)/2 ,x=(-sqrt(3)+5)/2

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- 3 (2 x - 5)^{2} + 13 = 4

x = \frac{3 + 5}{2}, x = \frac{- 3 + 5}{2}

Decimal Notation

x = 3.36602 \dots, x = 1.63397 \dots

Solution steps

- 3 (2 x - 5)^{2} + 13 = 4

Move

13

to the right side

- 3 (2 x - 5)^{2} = - 9

Divide both sides by

- 3

(2 x - 5)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 3 : x = \frac{3 + 5}{2}

Solve

2 x - 5 = - 3 : x = \frac{- 3 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 5}{2}, x = \frac{- 3 + 5}{2}

r^{2} - 3 r = 10

w^{2} + 13 w + 42 = 0

m, L m^{2} + R m + \frac{1}{C} = 0

4 0^{2} + x^{2} = 4 1^{2}

3 m^{2} + 5 m = 6

What are the solutions to the equation -3(2x-5)^2+13=4 ?
The solutions to the equation -3(2x-5)^2+13=4 are x=(sqrt(3)+5)/2 ,x=(-sqrt(3)+5)/2
Find the zeros of -3(2x-5)^2+13=4
The zeros of -3(2x-5)^2+13=4 are x=(sqrt(3)+5)/2 ,x=(-sqrt(3)+5)/2