What are the solutions to the equation 2k^2-3=5k ?

The solutions to the equation 2k^2-3=5k are k=3,k=-1/2

Find the zeros of 2k^2-3=5k

The zeros of 2k^2-3=5k are k=3,k=-1/2

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2 k^{2} - 3 = 5 k

k = 3, k = - \frac{1}{2}

Decimal Notation

k = 3, k = - 0.5

Solution steps

2 k^{2} - 3 = 5 k

Move

5 k

to the left side

2 k^{2} - 3 - 5 k = 0

Write in the standard form

a x^{2} + b x + c = 0

2 k^{2} - 5 k - 3 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

k_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, k_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

k = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

k = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

k = 3, k = - \frac{1}{2}

x^{2} - 6 x - 18 = 0

x, x^{2} + 5 x + 1 = 0

9 = x^{2} + 2 x + 1

0 = x^{2} - 7 x + 6

x^{2} + 15 x

What are the solutions to the equation 2k^2-3=5k ?
The solutions to the equation 2k^2-3=5k are k=3,k=-1/2
Find the zeros of 2k^2-3=5k
The zeros of 2k^2-3=5k are k=3,k=-1/2