What are the solutions to the equation 9=x^2+2x+1 ?

The solutions to the equation 9=x^2+2x+1 are x=2,x=-4

Find the zeros of 9=x^2+2x+1

The zeros of 9=x^2+2x+1 are x=2,x=-4

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9 = x^{2} + 2 x + 1

x = 2, x = - 4

Solution steps

9 = x^{2} + 2 x + 1

Switch sides

x^{2} + 2 x + 1 = 9

Move

9

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

0 = x^{2} - 7 x + 6

x^{2} + 15 x

36 x^{2} + 12 x + 1 = 18

a, n = 4 a^{2} - m

a^{2} + 10 a + 25 = 0

What are the solutions to the equation 9=x^2+2x+1 ?
The solutions to the equation 9=x^2+2x+1 are x=2,x=-4
Find the zeros of 9=x^2+2x+1
The zeros of 9=x^2+2x+1 are x=2,x=-4