What are the solutions to the equation 0=x^2-7x+6 ?

The solutions to the equation 0=x^2-7x+6 are x=6,x=1

Find the zeros of 0=x^2-7x+6

The zeros of 0=x^2-7x+6 are x=6,x=1

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0 = x^{2} - 7 x + 6

x = 6, x = 1

Solution steps

0 = x^{2} - 7 x + 6

Switch sides

x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

x = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

x = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 6, x = 1

x^{2} + 15 x

36 x^{2} + 12 x + 1 = 18

a, n = 4 a^{2} - m

a^{2} + 10 a + 25 = 0

- 3 x^{2} + 9 x = 0

What are the solutions to the equation 0=x^2-7x+6 ?
The solutions to the equation 0=x^2-7x+6 are x=6,x=1
Find the zeros of 0=x^2-7x+6
The zeros of 0=x^2-7x+6 are x=6,x=1