What are the solutions to the equation -48x^2-36x-6=0 ?

The solutions to the equation -48x^2-36x-6=0 are x=-1/2 ,x=-1/4

Find the zeros of -48x^2-36x-6=0

The zeros of -48x^2-36x-6=0 are x=-1/2 ,x=-1/4

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- 48 x^{2} - 36 x - 6 = 0

x = - \frac{1}{2}, x = - \frac{1}{4}

Decimal Notation

x = - 0.5, x = - 0.25

Solution steps

- 48 x^{2} - 36 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 ( - 48 ) ( - 6 )}{2 ( - 48 )}

(- 36)^{2} - 4 (- 48) (- 6) = 12

x_{1, 2} = \frac{- ( - 36 ) \pm 12}{2 ( - 48 )}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 12}{2 ( - 48 )}, x_{2} = \frac{- ( - 36 ) - 12}{2 ( - 48 )}

x = \frac{- ( - 36 ) + 12}{2 ( - 48 )} : - \frac{1}{2}

x = \frac{- ( - 36 ) - 12}{2 ( - 48 )} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{1}{4}

j (x) = - 4 x^{2} - 2 x + 2

x^{2} + x - 0.5 = 0

x^{2} - 4 x - 21 = 0

- 2 x^{2} + 9 x + 29 = - 6

x, 2 x^{2} - 3 x y + 3 y^{2} = 50

What are the solutions to the equation -48x^2-36x-6=0 ?
The solutions to the equation -48x^2-36x-6=0 are x=-1/2 ,x=-1/4
Find the zeros of -48x^2-36x-6=0
The zeros of -48x^2-36x-6=0 are x=-1/2 ,x=-1/4