What are the solutions to the equation q^2+8q+16=-5q^2+6q+416 ?

The solutions to the equation q^2+8q+16=-5q^2+6q+416 are q=8,q=-25/3

Find the zeros of q^2+8q+16=-5q^2+6q+416

The zeros of q^2+8q+16=-5q^2+6q+416 are q=8,q=-25/3

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q^{2} + 8 q + 16 = - 5 q^{2} + 6 q + 416

q = 8, q = - \frac{25}{3}

Decimal Notation

q = 8, q = - 8.33333 \dots

Solution steps

q^{2} + 8 q + 16 = - 5 q^{2} + 6 q + 416

Move

416

to the left side

q^{2} + 8 q - 400 = - 5 q^{2} + 6 q

Move

6 q

to the left side

q^{2} + 2 q - 400 = - 5 q^{2}

Move

5 q^{2}

to the left side

6 q^{2} + 2 q - 400 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 400 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 400) = 98

q_{1, 2} = \frac{- 2 \pm 98}{2 \cdot 6}

Separate the solutions

q_{1} = \frac{- 2 + 98}{2 \cdot 6}, q_{2} = \frac{- 2 - 98}{2 \cdot 6}

q = \frac{- 2 + 98}{2 \cdot 6} : 8

q = \frac{- 2 - 98}{2 \cdot 6} : - \frac{25}{3}

The solutions to the quadratic equation are:

q = 8, q = - \frac{25}{3}

2 x^{2} - 7 x - 11 = 0

5 x^{2} + 3 = x

5 x^{2} + 2 = 6

x^{2} - 3 x + 5

x^{2} - 3 x + 1

What are the solutions to the equation q^2+8q+16=-5q^2+6q+416 ?
The solutions to the equation q^2+8q+16=-5q^2+6q+416 are q=8,q=-25/3
Find the zeros of q^2+8q+16=-5q^2+6q+416
The zeros of q^2+8q+16=-5q^2+6q+416 are q=8,q=-25/3