What are the solutions to the equation m^2-4m+8=0 ?

The solutions to the equation m^2-4m+8=0 are m=2+2i,m=2-2i

Find the zeros of m^2-4m+8=0

The zeros of m^2-4m+8=0 are m=2+2i,m=2-2i

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m^{2} - 4 m + 8 = 0

m = 2 + 2 i, m = 2 - 2 i

Solution steps

m^{2} - 4 m + 8 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 8 : 4 i

m_{1, 2} = \frac{- ( - 4 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 4 i}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 4 i}{2 \cdot 1}

m = \frac{- ( - 4 ) + 4 i}{2 \cdot 1} : 2 + 2 i

m = \frac{- ( - 4 ) - 4 i}{2 \cdot 1} : 2 - 2 i

The solutions to the quadratic equation are:

m = 2 + 2 i, m = 2 - 2 i

(- 3 - x) \cdot (3 - x) = 0

21 x^{2} - 60 x + 40 = 0

3 + 5 z + z^{2} = 0

6 x^{2} + x - 15 = 8

3 x^{2} + 2 x + \frac{1}{4} = 0

What are the solutions to the equation m^2-4m+8=0 ?
The solutions to the equation m^2-4m+8=0 are m=2+2i,m=2-2i
Find the zeros of m^2-4m+8=0
The zeros of m^2-4m+8=0 are m=2+2i,m=2-2i