What are the solutions to the equation (3x+2)^2-49=0 ?

The solutions to the equation (3x+2)^2-49=0 are x= 5/3 ,x=-3

Find the zeros of (3x+2)^2-49=0

The zeros of (3x+2)^2-49=0 are x= 5/3 ,x=-3

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(3 x + 2)^{2} - 49 = 0

x = \frac{5}{3}, x = - 3

Decimal Notation

x = 1.66666 \dots, x = - 3

Solution steps

(3 x + 2)^{2} - 49 = 0

Move

49

to the right side

(3 x + 2)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 49 : x = \frac{5}{3}

Solve

3 x + 2 = - 49 : x = - 3

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 3

x^{2} + 1

5 m^{2} - 7 m - 11 = 0

m^{2} + 4 m - 12 = 0

x - 1 = x^{2} - 14 x + 49

3 x^{2} + 18 x

What are the solutions to the equation (3x+2)^2-49=0 ?
The solutions to the equation (3x+2)^2-49=0 are x= 5/3 ,x=-3
Find the zeros of (3x+2)^2-49=0
The zeros of (3x+2)^2-49=0 are x= 5/3 ,x=-3