What are the solutions to the equation (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0 ?

The solutions to the equation (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0 are x=3,x=-3

Find the zeros of (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0

The zeros of (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0 are x=3,x=-3

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\frac{x ^{2} - 5}{3} + \frac{4 x ^{2} - 1}{5} - \frac{14 x ^{2} - 1}{15} = 0

x = 3, x = - 3

Solution steps

\frac{x ^{2} - 5}{3} + \frac{4 x ^{2} - 1}{5} - \frac{14 x ^{2} - 1}{15} = 0

Multiply by LCM

5 (x^{2} - 5) + 3 (4 x^{2} - 1) - (14 x^{2} - 1) = 0

Expand

5 (x^{2} - 5) + 3 (4 x^{2} - 1) - (14 x^{2} - 1) : 3 x^{2} - 27

3 x^{2} - 27 = 0

Move

27

to the right side

3 x^{2} = 27

Divide both sides by

3

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

x, x^{2} + y^{2} - 8 x + 6 y + 29 = 0

4 m^{2} + 12 m + 9 = 0

5 x^{2} + 20 x + 20 = 0

x^{2} + 2 x - 15

- 0.0241 x^{2} + x + 5.5 = 0

What are the solutions to the equation (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0 ?
The solutions to the equation (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0 are x=3,x=-3
Find the zeros of (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0
The zeros of (x^2-5)/3+(4x^2-1)/5-(14x^2-1)/(15)=0 are x=3,x=-3