What are the solutions to the equation (2x-3)(3x-2)=0 ?

The solutions to the equation (2x-3)(3x-2)=0 are x= 3/2 ,x= 2/3

Find the zeros of (2x-3)(3x-2)=0

The zeros of (2x-3)(3x-2)=0 are x= 3/2 ,x= 2/3

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(2 x - 3) (3 x - 2) = 0

x = \frac{3}{2}, x = \frac{2}{3}

Decimal Notation

x = 1.5, x = 0.66666 \dots

Solution steps

(2 x - 3) (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or 3 x - 2 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{2}{3}

x, z = 1 + x^{2} + y^{2}

5 x^{2} + 2 = 4 x

x^{2} + \frac{2}{5} x + 3

6 x^{2} + 7 x + 3 = 0

x^{2} - 7 x - 18 = 0

What are the solutions to the equation (2x-3)(3x-2)=0 ?
The solutions to the equation (2x-3)(3x-2)=0 are x= 3/2 ,x= 2/3
Find the zeros of (2x-3)(3x-2)=0
The zeros of (2x-3)(3x-2)=0 are x= 3/2 ,x= 2/3