What are the solutions to the equation 5x^2-4x-20=0 ?

The solutions to the equation 5x^2-4x-20=0 are x=(2(1+sqrt(26)))/5 ,x=(2(1-sqrt(26)))/5

Find the zeros of 5x^2-4x-20=0

The zeros of 5x^2-4x-20=0 are x=(2(1+sqrt(26)))/5 ,x=(2(1-sqrt(26)))/5

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5 x^{2} - 4 x - 20 = 0

x = \frac{2 ( 1 + 26 )}{5}, x = \frac{2 ( 1 - 26 )}{5}

Decimal Notation

x = 2.43960 \dots, x = - 1.63960 \dots

Solution steps

5 x^{2} - 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 20 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 20) = 426

x_{1, 2} = \frac{- ( - 4 ) \pm 4 26}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 26}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 4 26}{2 \cdot 5}

x = \frac{- ( - 4 ) + 4 26}{2 \cdot 5} : \frac{2 ( 1 + 26 )}{5}

x = \frac{- ( - 4 ) - 4 26}{2 \cdot 5} : \frac{2 ( 1 - 26 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 1 + 26 )}{5}, x = \frac{2 ( 1 - 26 )}{5}

u^{2} - u - 2 = 0

12 x^{2} - 78 x + 93.5 = 0

4 x^{2} - 20 x + 25 = 0

x, 2 x^{2} - 3 y^{3} = 12

x, 2 x^{2} - 3 y^{3} = 10

What are the solutions to the equation 5x^2-4x-20=0 ?
The solutions to the equation 5x^2-4x-20=0 are x=(2(1+sqrt(26)))/5 ,x=(2(1-sqrt(26)))/5
Find the zeros of 5x^2-4x-20=0
The zeros of 5x^2-4x-20=0 are x=(2(1+sqrt(26)))/5 ,x=(2(1-sqrt(26)))/5