What are the solutions to the equation solvefor x,2x^2-3y^3=12 ?

The solutions to the equation solvefor x,2x^2-3y^3=12 are x=sqrt((12+3y^3)/2),x=-sqrt((12+3y^3)/2)

Find the zeros of solvefor x,2x^2-3y^3=12

The zeros of solvefor x,2x^2-3y^3=12 are x=sqrt((12+3y^3)/2),x=-sqrt((12+3y^3)/2)

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solve for

x, 2 x^{2} - 3 y^{3} = 12

x = \frac{12 + 3 y ^{3}}{2}, x = - \frac{12 + 3 y ^{3}}{2}

Solution steps

2 x^{2} - 3 y^{3} = 12

Move

3 y^{3}

to the right side

2 x^{2} = 12 + 3 y^{3}

Divide both sides by

2

x^{2} = \frac{12 + 3 y ^{3}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{12 + 3 y ^{3}}{2}, x = - \frac{12 + 3 y ^{3}}{2}

x, 2 x^{2} - 3 y^{3} = 10

4 x^{2} + 10 x + 25 = 0

a, a^{2} = 2 a x - x^{2}

- 5 x^{2} - 114 = 50 x - 9

t, (1 - t^{2}) x^{2} - 2 t^{2} x - (t^{2} + 1) = 0

What are the solutions to the equation solvefor x,2x^2-3y^3=12 ?
The solutions to the equation solvefor x,2x^2-3y^3=12 are x=sqrt((12+3y^3)/2),x=-sqrt((12+3y^3)/2)
Find the zeros of solvefor x,2x^2-3y^3=12
The zeros of solvefor x,2x^2-3y^3=12 are x=sqrt((12+3y^3)/2),x=-sqrt((12+3y^3)/2)