What are the solutions to the equation u^2-u-2=0 ?

The solutions to the equation u^2-u-2=0 are u=2,u=-1

Find the zeros of u^2-u-2=0

The zeros of u^2-u-2=0 are u=2,u=-1

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u^{2} - u - 2 = 0

u = 2, u = - 1

Solution steps

u^{2} - u - 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

u_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, u_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

u = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

u = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 2, u = - 1

12 x^{2} - 78 x + 93.5 = 0

4 x^{2} - 20 x + 25 = 0

x, 2 x^{2} - 3 y^{3} = 12

x, 2 x^{2} - 3 y^{3} = 10

4 x^{2} + 10 x + 25 = 0

What are the solutions to the equation u^2-u-2=0 ?
The solutions to the equation u^2-u-2=0 are u=2,u=-1
Find the zeros of u^2-u-2=0
The zeros of u^2-u-2=0 are u=2,u=-1