What are the solutions to the equation 4x^2+10x+25=0 ?

The solutions to the equation 4x^2+10x+25=0 are x=-5/4+i(5sqrt(3))/4 ,x=-5/4-i(5sqrt(3))/4

Find the zeros of 4x^2+10x+25=0

The zeros of 4x^2+10x+25=0 are x=-5/4+i(5sqrt(3))/4 ,x=-5/4-i(5sqrt(3))/4

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4 x^{2} + 10 x + 25 = 0

x = - \frac{5}{4} + i \frac{5 3}{4}, x = - \frac{5}{4} - i \frac{5 3}{4}

Solution steps

4 x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

Simplify

1 0^{2} - 4 \cdot 4 \cdot 25 : 103 i

x_{1, 2} = \frac{- 10 \pm 10 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 10 + 10 3 i}{2 \cdot 4}, x_{2} = \frac{- 10 - 10 3 i}{2 \cdot 4}

x = \frac{- 10 + 10 3 i}{2 \cdot 4} : - \frac{5}{4} + i \frac{5 3}{4}

x = \frac{- 10 - 10 3 i}{2 \cdot 4} : - \frac{5}{4} - i \frac{5 3}{4}

The solutions to the quadratic equation are:

x = - \frac{5}{4} + i \frac{5 3}{4}, x = - \frac{5}{4} - i \frac{5 3}{4}

a, a^{2} = 2 a x - x^{2}

- 5 x^{2} - 114 = 50 x - 9

t, (1 - t^{2}) x^{2} - 2 t^{2} x - (t^{2} + 1) = 0

- 4 x^{2} - 530 x + 265 = 0

10 x^{2} + 12 x + 2 = 0

What are the solutions to the equation 4x^2+10x+25=0 ?
The solutions to the equation 4x^2+10x+25=0 are x=-5/4+i(5sqrt(3))/4 ,x=-5/4-i(5sqrt(3))/4
Find the zeros of 4x^2+10x+25=0
The zeros of 4x^2+10x+25=0 are x=-5/4+i(5sqrt(3))/4 ,x=-5/4-i(5sqrt(3))/4