What are the solutions to the equation s^2+7s+10=0 ?

The solutions to the equation s^2+7s+10=0 are s=-2,s=-5

Find the zeros of s^2+7s+10=0

The zeros of s^2+7s+10=0 are s=-2,s=-5

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s^{2} + 7 s + 10 = 0

s = - 2, s = - 5

Solution steps

s^{2} + 7 s + 10 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

s_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 7 + 3}{2 \cdot 1}, s_{2} = \frac{- 7 - 3}{2 \cdot 1}

s = \frac{- 7 + 3}{2 \cdot 1} : - 2

s = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

s = - 2, s = - 5

2 x^{2} + 7 x + 9 = 0

λ^{2} - 5 λ + 6 = 0

0 = 12 x^{2} - 4

x^{2} + 9 x - 13 = 0

z^{2} + 2 z + 6 = 0

What are the solutions to the equation s^2+7s+10=0 ?
The solutions to the equation s^2+7s+10=0 are s=-2,s=-5
Find the zeros of s^2+7s+10=0
The zeros of s^2+7s+10=0 are s=-2,s=-5