What are the solutions to the equation λ^2-5λ+6=0 ?

The solutions to the equation λ^2-5λ+6=0 are λ=3,λ=2

Find the zeros of λ^2-5λ+6=0

The zeros of λ^2-5λ+6=0 are λ=3,λ=2

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λ^{2} - 5 λ + 6 = 0

λ = 3, λ = 2

Solution steps

λ^{2} - 5 λ + 6 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

λ_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, λ_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

λ = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

λ = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

λ = 3, λ = 2

0 = 12 x^{2} - 4

x^{2} + 9 x - 13 = 0

z^{2} + 2 z + 6 = 0

8 x (x + 2) - 8 = 2 x (2 + x) + 9

x^{2} + 8 x + 14 = 0

What are the solutions to the equation λ^2-5λ+6=0 ?
The solutions to the equation λ^2-5λ+6=0 are λ=3,λ=2
Find the zeros of λ^2-5λ+6=0
The zeros of λ^2-5λ+6=0 are λ=3,λ=2