What are the solutions to the equation z^2+2z+6=0 ?

The solutions to the equation z^2+2z+6=0 are z=-1+sqrt(5)i,z=-1-sqrt(5)i

Find the zeros of z^2+2z+6=0

The zeros of z^2+2z+6=0 are z=-1+sqrt(5)i,z=-1-sqrt(5)i

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z^{2} + 2 z + 6 = 0

z = - 1 + 5 i, z = - 1 - 5 i

Solution steps

z^{2} + 2 z + 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 6 : 25 i

z_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 2 + 2 5 i}{2 \cdot 1}, z_{2} = \frac{- 2 - 2 5 i}{2 \cdot 1}

z = \frac{- 2 + 2 5 i}{2 \cdot 1} : - 1 + 5 i

z = \frac{- 2 - 2 5 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

z = - 1 + 5 i, z = - 1 - 5 i

8 x (x + 2) - 8 = 2 x (2 + x) + 9

x^{2} + 8 x + 14 = 0

x^{2} - 16 x + 63 = 0

2 x^{2} - 20 = 6 x

3 x^{2} - x + 10 = 0

What are the solutions to the equation z^2+2z+6=0 ?
The solutions to the equation z^2+2z+6=0 are z=-1+sqrt(5)i,z=-1-sqrt(5)i
Find the zeros of z^2+2z+6=0
The zeros of z^2+2z+6=0 are z=-1+sqrt(5)i,z=-1-sqrt(5)i