What are the solutions to the equation 3x^2+8=x^2 ?

The solutions to the equation 3x^2+8=x^2 are x=2i,x=-2i

Find the zeros of 3x^2+8=x^2

The zeros of 3x^2+8=x^2 are x=2i,x=-2i

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3 x^{2} + 8 = x^{2}

x = 2 i, x = - 2 i

Solution steps

3 x^{2} + 8 = x^{2}

Move

8

to the right side

3 x^{2} = x^{2} - 8

Move

x^{2}

to the left side

2 x^{2} = - 8

Divide both sides by

2

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

2 x^{2} - 8 x - 90 = 0

- 3 x^{2} - 8 x + 16 = 0

x^{2} + 2 x - 15 = 0

k^{2} = 6 k - 10

x, 16 y^{2} - x^{2} + 2 x + 64 y + 63 = 0

What are the solutions to the equation 3x^2+8=x^2 ?
The solutions to the equation 3x^2+8=x^2 are x=2i,x=-2i
Find the zeros of 3x^2+8=x^2
The zeros of 3x^2+8=x^2 are x=2i,x=-2i