What are the solutions to the equation x^2-3x+3=3 ?

The solutions to the equation x^2-3x+3=3 are x=3,x=0

Find the zeros of x^2-3x+3=3

The zeros of x^2-3x+3=3 are x=3,x=0

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x^{2} - 3 x + 3 = 3

x = 3, x = 0

Solution steps

x^{2} - 3 x + 3 = 3

Move

3

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

2 y^{2} - 5 y - 3 = 0

6 x^{2} - 12 x - 2

9 x^{2} - 72 x = 0

x^{2} - \frac{6}{7} x + 2

x, x^{2} - 2 x y + 3 y^{2} = 4

What are the solutions to the equation x^2-3x+3=3 ?
The solutions to the equation x^2-3x+3=3 are x=3,x=0
Find the zeros of x^2-3x+3=3
The zeros of x^2-3x+3=3 are x=3,x=0